For the reaction shown, which statement is co | vedclass

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(C) The reaction shown is the Hofmann bromamide degradation of $2$-methylbenzamide using $NaOBr$, which yields $2$-methylaniline (o-toluidine) as Prod

Vedclass · Accepted Answer

It has one isomer of $2^\circ$ amine.

Vedclass · Answer

(C) The reaction shown is the Hofmann bromamide degradation of $2$-methylbenzamide using $NaOBr$, which yields $2$-methylaniline (o-toluidine) as Product "$X$".$2$-methylaniline is a primary aromatic amine $(Ar-NH_2)$.$1$. It reacts with Hinsberg's reagent (benzenesulfonyl chloride) to form a sulfonamide, which is soluble in alkali.$2$. It reacts with nitrous acid $(HNO_2)$ at $0-5^{\circ}C$ to form a diazonium salt, which gives a positive Azo dye test with $\beta$-naphthol.$3$. It is a primary amine, and its $2^\circ$ amine isomer is $N$-methylaniline $(C_6H_5NHCH_3)$.$4$. Primary aromatic amines are generally insoluble in aqueous $NaOH$ because they are basic in nature, not acidic.Therefore, the correct statement is that it has one isomer of $2^\circ$ amine, which is $N$-methylaniline.

For the reaction shown, which statement is correct for Product "$X$"?

Similar Questions

Which one among the following statements is true?

What is the major product of the reaction when the given compound undergoes Hofmann exhaustive methylation?

What product is formed when benzamide is reacted with $POCl_3$?

The final product $C$,obtained in the following reaction sequence,would be:
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Consider the following reaction:
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What is $Y$?

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